Question : Problem: LCD Display

Hi Everyone,

Following is my code to display some msgs on LCD.I cant get the "range" displayed on the second line. Please help.

//pic16f877a running at 4 Mhz
// 2x16 LCD, 4 bit mode
#include

int RTC = 0;
int Dlay;

static volatile bit RS @ (unsigned) & PORTD*8 + 0;
static volatile bit EN @ (unsigned) & PORTD*8 + 2;
static volatile bit RW @ (unsigned) & PORTD*8 + 1;

char Message[17] = "*PARKING SENSOR*";
char Msg[7]="Range=";

void interrupt tmr0_int(void)
{
if(T0IF)
{
T0IF = 0;
RTC++;
}
}

void LCDNibble(char Nibble)
{
PORTD= Nibble;
EN=1;
EN=0;
}

void LCDByte(char Byte)
{
PORTD= (PORTD & 0x0F )|( Byte & 0xF0);
EN=1;
EN=0;
Dlay= RTC+6;
while(Dlay!=RTC);

PORTD= (PORTD & 0x0F)| (( Byte<<4) & 0xF0);
EN=1;
EN=0;
Dlay= RTC+6;
while(Dlay!=RTC);
}

void main()
{
int i,j;
OPTION = 0x01;  //   /4 prescale
TMR0=0;
T0IE=1;
GIE=1;
RBPU=0;
RW=0;

TRISD=0x00;
PORTD=0x00;

Dlay= RTC+ 20;
while(Dlay!=RTC);

LCDNibble(0x30);

Dlay= RTC+6;
while(Dlay!=RTC);

LCDNibble(0x30);

Dlay= RTC+1;
while(Dlay!=RTC);

LCDNibble(0x30);

Dlay= RTC+1;
while(Dlay!=RTC);

LCDNibble(0x20);

Dlay= RTC+1;
while(Dlay!=RTC);

LCDByte(0x28);
LCDByte(0x08);
LCDByte(0x01);
LCDByte(0x06);
LCDByte(0x0E);

RS=1;

for(i=0;i<16;i++)
LCDByte(Message);


for(j=0;j<6;j++)
LCDByte(Msg[j]);




while(1)
{

}
}

Answer : Problem: LCD Display

Try adding this function.

// Moves the cursor to the desired position.
LCD_Locate(unsigned char Position)
{


      RS = 0;
      LCDByte(0x80 + Position);
        RS = 1;
}

Then add this code before the second For

LCD_Locate(0x40);

 You can create a function called LCD_Print for example that will receive arguments like (String1, String2) for the two lines... or (String, Position) so you don't need to worry about the location of the cursor.

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